Course Content
Precalculus

Explanation

If f(x) ≤ g(x) ≤ h(x) near c and:

lim (x→c) f(x) = lim (x→c) h(x) = L

Then lim (x→c) g(x) = L

Example:
−x² ≤ x²sin(1/x) ≤ x² → lim (x→0) x²sin(1/x) = 0


Quiz

  1. What is squeezed in the squeeze theorem?

  2. If bounds have the same limit, what about middle function?

  3. Example bounds? −x² ≤ g(x) ≤ x²

  4. lim (x→0) x²sin(1/x) = ?

  5. Can it solve tricky oscillating functions?

Answer Key

  1. Function between two others

  2. It has the same limit

  3. −x² and x²

  4. 0

  5. Yes

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